(e^(x)e^(iy))/e=-ie^2

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Solution for (e^(x)e^(iy))/e=-ie^2 equation:


Oblicz to!

2;5;1;3

(2/3)*x^(1/3)-((5*x^(2/3))/3) = 0

x^(2/3)-x^(5/3) = 0

a = (B*h)/2

(1/2)*x-1 = (1/5)*x-2

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